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新人教版高中英語必修3Unit 1 Festivals and Celebrations-Reading for writing教學設計二
Step 3 Analyzing article structureActivity 31. Teachers raise questions to guide students to analyze the chapter structure of this diary and think about how to describe the festival experience. (1)What should be included in the opening/body/closing paragraph(s)?(2)How did the writer arrange his/her ideas?(3)What kind of interesting details did the writer describe?(4)How did the writer describe his/her feelings/emotions during the event?2. Students read and compare the three sentence patterns in activity 2. Try to rewrite the first paragraph of the diary with these three sentence patterns. After that, students exchange corrections with their partners. Such as:●This was my first time spending three days experiencing the Naadam Festival in China’s Inner Mongolia Autonomous Region and it was an enjoyable and exciting experience. ●I'll never forget my experience at the Naadam Festival because it was my first time to watch the exciting Mongolian games of horse racing, wrestling, and archery so closely. ●I'll always remember my first experience at the Naadam Festival in China’s Inner Mongolia Autonomous Region because it was so amazing to spend three days witnessing a grand Mongolian ceremony. Step 4 Accumulation of statementsActivity 41. Ask the students to read the diary again. Look for sentences that express feelings and emotions, especially those with the -ing form and the past participle. Such as:● …h(huán)orse racing, wrestling, and archery, which are all so exciting to watch. ● some amazing performances● I was surprised to see…● I was a little worried about. . . ● feeling really tiredOther emotional statements:●I absolutely enjoyed the archery, too, but the horse races were my favourite part. ●I'm finally back home now, feeling really tired, but celebrating Naadam with my friend was totally worth it. ●He invited me back for the winter to stay in a traditional Mongolian tent and cat hot pot. I can’t wait!2. In addition to the use of the -ing form and the past participle, the teacher should guide the students in the appreciation of these statements, ask them to memorize them, and encourage them to use them reasonably in writing practice.
新人教版高中英語必修3Unit 4 Space Exploration-Reading and Thinking教學設計二
The theme of this unit focuses on “space exploration.” Students will learn about the training and experience needed to become an astronaut. The text is mainly about the development of space exploration. On the one hand, the text helps students to have a good understanding about the great feats humans have achieved, on the other hand, they will further understand the contributions that we Chinese have achieved, and feel confident and proud about our homeland and strengthen their love for our country. The teacher should instruct students to aim high and study harder to make great progress in the space career if possible.1. Read about the development and value of space exploration.2. Explore the mysteries of the universe and the achievements in space exploration.3. Skillfully use the vocabulary of this text to cultivate self-study ability 4. Develop cooperative learning ability through discussion.1. Enable the Ss to talk about the development and value of space exploration.2. Guide the Ss to summarize the main idea of each paragraph as well as the main idea of the text.3. Help Ss comprehend the main reasons for space exploration. Multi-media, textbook, notebooks.Step 1: Warming up and predictionLook at the title and the pictures of the text and predict what the text will be about?2. What are the main reasons for space exploration?
新人教版高中英語必修3Unit 4 Space Exploration-Reading for Writing教學設計二
⑦在我看來, 探索太空是值得的。As far as I am concerned, it is worthwhile to explore the space.Step 10 Writing---draftRecently, students in our class have had heated a discussion on whether space is worth exploring. Students hold different ideas about it.30% of us think space exploration is not worthwhile. They think space is too far away from us and our daily life and is a waste of money. And the money spent on space exploration can be used to solve the earth’s problems such as starvation and pollution.On the other hand，70% think space is worth exploring because we have benefited a lot from it，such as using satellites for communication and weather forecast. What’s more，with further space research，we may solve the population problem by moving to other planets one day. Also，space research will enable us to find new sources to solve the problem of energy shortages on the earth.As far as I am concerned, it is worthwhile to explore the space. Not only can it promote the development of society but also enrich our life. Step 11 Pair workExchange drafts with a partner. Use this checklist to help your partner revise his/her draft.1.Does the writer explain why he/she changed/wanted to change?2.Does the writer tell how the changes have improved or will improve his/her life?3.Is the text well－organised?4.Does the writer use words and expressions to show similarities and differences?5.Are there any grammar or spelling errors?6.Does the writer use correct punctuation？
新人教版高中英語必修3Unit 5 The value of money-Reading and Thinking教學設計二
? Could you offer me some kind of work here?? I don’t want your charity, I just want an honest job.? Careless: I landed in Britain by accident.Step 7:Consolidation.? Find Henry? Roderick and Oliver were I .making a bet when they saw Henry, a poor young man. ? Know Henry? About a month ago, Henry was sailing and later he found himself carried out to sea by a strong wind. Fortunately, he 2.was spotted by a ship. And it was the ship that brought him to 3.England? Offer money to Henry ? Oliver and Roderick gave Henry a letter and told him that there was money in it. They 4.persuaded him to accept it, and made him 5.promise that it wouldn't be opened until 2 o'clock.Step 8：Language pointsa large amount of: a large quantity of; a great deal ofe.g. They bought a large amount of furniture before they moved their new house.make a bet: make an arrangement to risk money, etc. on an event of which the result is doubtful.e.g. We made a bet on the result of the match.permit sb to do something: allow somebody to do somethinge.g. My mother doesn’t permit me to ride in the street after it rained.by accident: as a result of chancee.g. I only found it by accident.stare at: look at somebody or something with the eyes wide open in a fixed gaze( in astonishment, wonder, fear, etc)to be honest: to tell you the truth; to be franke.g. To be honest, I don’t think we have a chance of winning.Step7 Homework:What do you think will happen to Henry? Will the bank-note help him or get him into trouble?
新人教版高中英語必修3Unit 5 The Value of Money-Reading for Writing教學設計二
2. 您能看到, 我頭發(fā)太長了。You can see that my hair is much too long.3. 無論什么時候, 只要您想回來就回來。Please come back whenever you want.4. 您僅有很少的頭發(fā)要理! You only have too little hair to cut !5. 為您服務是我的榮幸！It is my honour to serve you!Step 9 Writing(Henry is walking down the street when he sees a sign for a place that cuts hair. He decides to have it cut. )H=Henry B=BarberH: Good afternoon, I’d like to have my hair cut, if I may. (The barber looks at Henry’s hair and continues cutting another man’s hair. ) Er, I’d really like a haircut. As you can see it’s much too long. B: (in a rude manner) Yes, I can see that. Indeed, I can. H: Fine, well, I’ll have a seat then. (He sits in one of the barber’s chairs. The barber turns to look at Henry. )B: It’s quite expensive here, you know! Are you sure you can afford it?H: Yes. I think so. (After his hair is cut, the barber tells Henry how much he must pay. Henry shows the barber the bank note. )B: Why Mr. . . (looks shocked)H: Adams. Henry Adams. I’m sorry. I don’t have any change. B: Please don’t worry! (wearing a big smile) Nothing to worry about! Nothing at all! Please come back whenever you want, even if you only have too little hair to cut! It will be my honour to serve you!Step 10 Pair workExchange drafts with a partner. Use this checklist to help your partner revise his/her draft.1. Are all the elements of a play included and in good order ?2. Do the character use suitable language ?3. Are the stage directions clear and useful ?4. Is the plot clear and exciting enough ?
人教版新課標高中物理必修1牛頓第三定律說課稿2篇
問：為什么會出現(xiàn)這樣的情況，男女生之間的拉力存在著怎樣的大小關系？進一步求證這兩個力的大小關系經過共同討論，得方案：把兩個彈簧秤勾在一起，重現(xiàn)拔河比賽，分三種情況進行。（通過攝像頭把彈簧秤的讀數(shù)放大）兩彈簧稱勾在一起拉，處于靜止不動時（即拔河比賽，雙方處于僵持狀態(tài)）兩彈簧稱勾在一起拉，并向一方運動（即比賽繩子被拉向一方時的狀態(tài)）3、兩彈簧稱勾在一起拉，一方方向慢慢改變（兩力方向始終在一條直線上）實驗結論：兩彈簧稱的讀數(shù)的變化總是相同的，大小相等，方向相反。得到牛頓第三定律：追問：既然兩個力大小相等，那么拔河比賽為什么還存在勝負之分？講清作用力與反作用力作用的受力物體不同，并和學生討論如何做才會獲勝。回應課前問題：“以卵擊石”為什么雞蛋碎？
人教版高中政治必修4綜合探究：堅持唯物辯證法，反對形而上學教案
5．循環(huán)經濟當前，發(fā)展循環(huán)經濟和知識經濟已成為國際社會的兩大趨勢，有的發(fā)達國家甚至以立法的方式加以推進。循環(huán)經濟本質上是一種生態(tài)經濟，它要求運用生態(tài)學規(guī)律而不是機械的規(guī)律來指導人類社會的經濟活動，減量化、再利用和資源化是其三大原則。傳統(tǒng)經濟是一種“資源——產品——污染排放”單向流動的線性經濟，特征是高開采、低利用、高排放；與之不同，循環(huán)經濟倡導的是一種與環(huán)境和諧的經濟發(fā)展模式，它要求把經濟活動組織成一個“資源——產品——再生資源”的反饋式流程，特征是低開采、高利用、低排放。目前，我國已經把發(fā)展循環(huán)經濟作為編制“十一五”規(guī)劃的重要指導原則。6．當心被優(yōu)勢“絆倒”有三個旅行者同時住進一家旅店，早上同時出門旅游。晚上歸來時，拿傘的人淋得渾身是水，拿拐杖的人跌得滿身是傷，而什么也沒有帶的人卻安然無恙。
人教版高中語文必修3《愛的奉獻 學習議論中的記敘》說課稿
教學過程：（一）導入：課前放《愛的奉獻》歌曲，同時不斷播放一些有關“愛”的主題的圖片，渲染一種情感氛圍。師說：同學們，誰能說說這組圖片的主題應該是什么？生（七嘴八舌）：母愛，不對是親情……是友情、還有人與人互相幫助……那組軍人圖片是說保衛(wèi)國家，應該是愛國……那徐本禹和感動中國呢？…………生答：是關于愛的方面師說：不錯，是關于愛的方面。那么同學們，今天就以“愛的奉獻”為話題，來寫一篇議論文如何？生答：老師，還是寫記敘文吧。生答：就是，要不議論文寫出來也象記敘文。師問：為什么？生答：老師，這個話題太有話說了，一舉例子就收不住了，怎么看怎么象記敘文。生答：就是，再用一點形容詞，就更象了。眾人樂。師說：那么同學們誰能告訴我，為什么會出現(xiàn)這種問題？一生小聲說：還不是我們笨，不會寫。師說：不是笨，也不是不會寫，你們想為什么記敘文就會寫，一到議論文就不會了，那是因為同學們沒有明白議論文中的記敘與記敘文中的記敘有什么不同，所以一寫起議論文中的記敘，還是按照記敘文的寫法寫作，這自然就不行了。那好，今天我們就從如何寫議論文中的記敘講起。
保護野生動物國旗下講話
同學們：早上好！根據《中華人民共和國野生動物保護法》規(guī)定，每年十一月為全國“保護野生動物宣傳月”。早在100多年前，意大利傳教士圣·弗朗西斯就倡導在每年的10月4日“向獻愛心給人類的動物們致謝”。為了紀念他，人們把10月4日定為“世界動物日”。每年的這一天，世界各國的人們都會以不同的形式開展愛護動物的各種活動。人類進化的每一步都離不開我們身邊的動物。不幸的是，隨著城市的擴張、環(huán)境的污染、人類對自然資源的無度開采，動物的家園被侵犯了，它們的生命正受到威脅。從娛樂項目中作為活靶子的野兔，到身體里永遠插著管子被活取膽汁的月牙熊；從頃刻間轟然倒下的百年老林，到可可西里依偎在母親尸體旁取暖的小藏羚羊……無不記著人類對動物、對大自然犯下的罪行。在這個孤寂的星球上，動物是我們的芳鄰，大自然是我們的家。愛護動物、保護環(huán)境就是愛護我們自己。同學們，一個人保護動物的能力有限，
圓的標準方程教學設計人教A版高中數(shù)學選擇性必修第一冊
(1)幾何法它是利用圖形的幾何性質,如圓的性質等,直接求出圓的圓心和半徑,代入圓的標準方程,從而得到圓的標準方程.(2)待定系數(shù)法由三個獨立條件得到三個方程,解方程組以得到圓的標準方程中三個參數(shù),從而確定圓的標準方程.它是求圓的方程最常用的方法,一般步驟是:①設——設所求圓的方程為(x-a)2+(y-b)2=r2;②列——由已知條件,建立關于a,b,r的方程組;③解——解方程組,求出a,b,r;④代——將a,b,r代入所設方程,得所求圓的方程.跟蹤訓練1．已知△ABC的三個頂點坐標分別為A(0,5)，B(1，－2)，C(－3，－4)，求該三角形的外接圓的方程．[解] 法一：設所求圓的標準方程為(x－a)2＋(y－b)2＝r2.因為A(0,5)，B(1,－2)，C(－3,－4)都在圓上，所以它們的坐標都滿足圓的標準方程，于是有?0－a?2＋?5－b?2＝r2，?1－a?2＋?－2－b?2＝r2，?－3－a?2＋?－4－b?2＝r2.解得a＝－3，b＝1，r＝5.故所求圓的標準方程是(x＋3)2＋(y－1)2＝25.
圓與圓的位置關系教學設計人教A版高中數(shù)學選擇性必修第一冊
1.兩圓x2+y2-1=0和x2+y2-4x+2y-4=0的位置關系是( )A.內切 B.相交 C.外切 D.外離解析:圓x2+y2-1=0表示以O1(0,0)點為圓心,以R1=1為半徑的圓.圓x2+y2-4x+2y-4=0表示以O2(2,-1)點為圓心,以R2=3為半徑的圓.∵|O1O2|=√5,∴R2-R1<|O1O2|<R2+R1,∴圓x2+y2-1=0和圓x2+y2-4x+2y-4=0相交.答案:B2.圓C1:x2+y2-12x-2y-13=0和圓C2:x2+y2+12x+16y-25=0的公共弦所在的直線方程是 . 解析:兩圓的方程相減得公共弦所在的直線方程為4x+3y-2=0.答案:4x+3y-2=03.半徑為6的圓與x軸相切,且與圓x2+(y-3)2=1內切,則此圓的方程為( )A.(x-4)2+(y-6)2=16 B.(x±4)2+(y-6)2=16C.(x-4)2+(y-6)2=36 D.(x±4)2+(y-6)2=36解析:設所求圓心坐標為(a,b),則|b|=6.由題意,得a2+(b-3)2=(6-1)2=25.若b=6,則a=±4;若b=-6,則a無解.故所求圓方程為(x±4)2+(y-6)2=36.答案:D4.若圓C1:x2+y2=4與圓C2:x2+y2-2ax+a2-1=0內切,則a等于 . 解析:圓C1的圓心C1(0,0),半徑r1=2.圓C2可化為(x-a)2+y2=1,即圓心C2(a,0),半徑r2=1,若兩圓內切,需|C1C2|=√(a^2+0^2 )=2-1=1.解得a=±1. 答案:±1 5. 已知兩個圓C1:x2+y2=4,C2:x2+y2-2x-4y+4=0,直線l:x+2y=0,求經過C1和C2的交點且和l相切的圓的方程.解:設所求圓的方程為x2+y2+4-2x-4y+λ(x2+y2-4)=0,即(1+λ)x2+(1+λ)y2-2x-4y+4(1-λ)=0.所以圓心為 1/(1+λ),2/(1+λ) ,半徑為1/2 √((("-" 2)/(1+λ)) ^2+(("-" 4)/(1+λ)) ^2 "-" 16((1"-" λ)/(1+λ))),即|1/(1+λ)+4/(1+λ)|/√5=1/2 √((4+16"-" 16"(" 1"-" λ^2 ")" )/("(" 1+λ")" ^2 )).解得λ=±1,舍去λ=-1,圓x2+y2=4顯然不符合題意,故所求圓的方程為x2+y2-x-2y=0.
點到直線的距離公式教學設計人教A版高中數(shù)學選擇性必修第一冊
4.已知△ABC三個頂點坐標A(－1,3)，B(－3,0)，C(1,2)，求△ABC的面積S.【解析】由直線方程的兩點式得直線BC的方程為 ＝ ，即x－2y＋3＝0，由兩點間距離公式得|BC|＝ ，點A到BC的距離為d，即為BC邊上的高，d＝ ，所以S＝ |BC|·d＝ ×2 × ＝4，即△ABC的面積為4.5.已知直線l經過點P(0,2),且A(1,1),B(-3,1)兩點到直線l的距離相等,求直線l的方程.解:(方法一)∵點A(1,1)與B(-3,1)到y(tǒng)軸的距離不相等,∴直線l的斜率存在,設為k.又直線l在y軸上的截距為2,則直線l的方程為y=kx+2,即kx-y+2=0.由點A(1,1)與B(-3,1)到直線l的距離相等,∴直線l的方程是y=2或x-y+2=0.得("|" k"-" 1+2"|" )/√(k^2+1)=("|-" 3k"-" 1+2"|" )/√(k^2+1),解得k=0或k=1.(方法二)當直線l過線段AB的中點時,A,B兩點到直線l的距離相等.∵AB的中點是(-1,1),又直線l過點P(0,2),∴直線l的方程是x-y+2=0.當直線l∥AB時,A,B兩點到直線l的距離相等.∵直線AB的斜率為0,∴直線l的斜率為0,∴直線l的方程為y=2.綜上所述,滿足條件的直線l的方程是x-y+2=0或y=2.
兩點間的距離公式教學設計人教A版高中數(shù)學選擇性必修第一冊
一、情境導學在一條筆直的公路同側有兩個大型小區(qū),現(xiàn)在計劃在公路上某處建一個公交站點C,以方便居住在兩個小區(qū)住戶的出行.如何選址能使站點到兩個小區(qū)的距離之和最小?二、探究新知問題1.在數(shù)軸上已知兩點A、B，如何求A、B兩點間的距離？提示：|AB|＝|xA－xB|.問題2：在平面直角坐標系中能否利用數(shù)軸上兩點間的距離求出任意兩點間距離？探究.當x1≠x2，y1≠y2時，|P1P2|＝？請簡單說明理由．提示：可以，構造直角三角形利用勾股定理求解．答案：如圖，在Rt △P1QP2中，|P1P2|2＝|P1Q|2＋|QP2|2，所以|P1P2|＝?x2－x1?2＋?y2－y1?2.即兩點P1(x1，y1)，P2(x2，y2)間的距離|P1P2|＝?x2－x1?2＋?y2－y1?2.你還能用其它方法證明這個公式嗎？2．兩點間距離公式的理解(1)此公式與兩點的先后順序無關，也就是說公式也可寫成|P1P2|＝?x2－x1?2＋?y2－y1?2.(2)當直線P1P2平行于x軸時，|P1P2|＝|x2－x1|.當直線P1P2平行于y軸時，|P1P2|＝|y2－y1|.
兩條平行線間的距離教學設計人教A版高中數(shù)學選擇性必修第一冊
一、情境導學前面我們已經得到了兩點間的距離公式，點到直線的距離公式，關于平面上的距離問題，兩條直線間的距離也是值得研究的。思考1：立定跳遠測量的什么距離？A.兩平行線的距離 B.點到直線的距離 C. 點到點的距離二、探究新知思考2：已知兩條平行直線l_1,l_2的方程，如何求l_1 〖與l〗_2間的距離？根據兩條平行直線間距離的含義，在直線l_1上取任一點P（x_0,y_0 ），,點P（x_0,y_0 ）到直線l_2的距離就是直線l_1與直線l_2間的距離，這樣求兩條平行線間的距離就轉化為求點到直線的距離。兩條平行直線間的距離1. 定義：夾在兩平行線間的__________的長.公垂線段2. 圖示： 3. 求法：轉化為點到直線的距離.1．原點到直線x＋2y－5＝0的距離是( )A．2 B．3 C．2 D．5D [d＝|－5|12＋22＝5.選D.]
兩直線的交點坐標教學設計人教A版高中數(shù)學選擇性必修第一冊
1.直線2x+y+8=0和直線x+y-1=0的交點坐標是( )A.(-9,-10) B.(-9,10) C.(9,10) D.(9,-10)解析:解方程組{■(2x+y+8=0"," @x+y"-" 1=0"," )┤得{■(x="-" 9"," @y=10"," )┤即交點坐標是(-9,10).答案:B 2.直線2x+3y-k=0和直線x-ky+12=0的交點在x軸上,則k的值為( )A.-24 B.24 C.6 D.± 6解析:∵直線2x+3y-k=0和直線x-ky+12=0的交點在x軸上,可設交點坐標為(a,0),∴{■(2a"-" k=0"," @a+12=0"," )┤解得{■(a="-" 12"," @k="-" 24"," )┤故選A.答案:A 3.已知直線l1:ax+y-6=0與l2:x+(a-2)y+a-1=0相交于點P,若l1⊥l2,則點P的坐標為 . 解析:∵直線l1:ax+y-6=0與l2:x+(a-2)y+a-1=0相交于點P,且l1⊥l2,∴a×1+1×(a-2)=0,解得a=1,聯(lián)立方程{■(x+y"-" 6=0"," @x"-" y=0"," )┤易得x=3,y=3,∴點P的坐標為(3,3).答案:(3,3) 4.求證:不論m為何值,直線(m-1)x+(2m-1)y=m-5都通過一定點. 證明:將原方程按m的降冪排列,整理得(x+2y-1)m-(x+y-5)=0,此式對于m的任意實數(shù)值都成立,根據恒等式的要求,m的一次項系數(shù)與常數(shù)項均等于零,故有{■(x+2y"-" 1=0"," @x+y"-" 5=0"," )┤解得{■(x=9"," @y="-" 4"." )┤
圓的一般方程教學設計人教A版高中數(shù)學選擇性必修第一冊
情境導學前面我們已討論了圓的標準方程為(x-a)2+(y-b)2=r2,現(xiàn)將其展開可得：x2+y2-2ax-2bx+a2+b2-r2=0.可見,任何一個圓的方程都可以變形x2+y2+Dx+Ey+F=0的形式.請大家思考一下,形如x2+y2+Dx+Ey+F=0的方程表示的曲線是不是圓?下面我們來探討這一方面的問題.探究新知例如,對于方程x^2+y^2-2x-4y+6=0,對其進行配方，得〖(x-1)〗^2+(〖y-2)〗^2=-1,因為任意一點的坐標 (x,y) 都不滿足這個方程，所以這個方程不表示任何圖形，所以形如x2+y2+Dx+Ey+F=0的方程不一定能通過恒等變換為圓的標準方程，這表明形如x2+y2+Dx+Ey+F=0的方程不一定是圓的方程.一、圓的一般方程（1）當D2+E2-4F>0時,方程x2+y2+Dx+Ey+F=0表示以(-D/2,-E/2)為圓心,1/2 √(D^2+E^2 "-" 4F)為半徑的圓,將方程x2+y2+Dx+Ey+F=0，配方可得〖(x+D/2)〗^2+(〖y+E/2)〗^2=(D^2+E^2-4F)/4（2）當D2+E2-4F=0時,方程x2+y2+Dx+Ey+F=0，表示一個點(-D/2,-E/2)（3）當D2+E2-4F0);
直線的點斜式方程教學設計人教A版高中數(shù)學選擇性必修第一冊
【答案】B [由直線方程知直線斜率為3，令x＝0可得在y軸上的截距為y＝－3.故選B.]3．已知直線l1過點P(2,1)且與直線l2：y＝x＋1垂直，則l1的點斜式方程為________．【答案】y－1＝－(x－2) [直線l2的斜率k2＝1，故l1的斜率為－1，所以l1的點斜式方程為y－1＝－(x－2)．]4．已知兩條直線y＝ax－2和y＝(2－a)x＋1互相平行，則a＝________. 【答案】1 [由題意得a＝2－a，解得a＝1.]5.無論k取何值,直線y-2=k(x+1)所過的定點是 . 【答案】(-1,2)6．直線l經過點P(3,4)，它的傾斜角是直線y＝3x＋3的傾斜角的2倍，求直線l的點斜式方程．【答案】直線y＝3x＋3的斜率k＝3，則其傾斜角α＝60°，所以直線l的傾斜角為120°.以直線l的斜率為k′＝tan 120°＝－3.所以直線l的點斜式方程為y－4＝－3(x－3)．
直線與圓的位置關系教學設計人教A版高中數(shù)學選擇性必修第一冊
切線方程的求法1.求過圓上一點P(x0,y0)的圓的切線方程:先求切點與圓心連線的斜率k,則由垂直關系,切線斜率為-1/k,由點斜式方程可求得切線方程.若k=0或斜率不存在,則由圖形可直接得切線方程為y=b或x=a.2.求過圓外一點P(x0,y0)的圓的切線時,常用幾何方法求解設切線方程為y-y0=k(x-x0),即kx-y-kx0+y0=0,由圓心到直線的距離等于半徑,可求得k,進而切線方程即可求出.但要注意,此時的切線有兩條,若求出的k值只有一個時,則另一條切線的斜率一定不存在,可通過數(shù)形結合求出.例3 求直線l:3x+y-6=0被圓C:x2+y2-2y-4=0截得的弦長.思路分析:解法一求出直線與圓的交點坐標,解法二利用弦長公式,解法三利用幾何法作出直角三角形,三種解法都可求得弦長.解法一由{■(3x+y"-" 6=0"," @x^2+y^2 "-" 2y"-" 4=0"," )┤得交點A(1,3),B(2,0),故弦AB的長為|AB|=√("(" 2"-" 1")" ^2+"(" 0"-" 3")" ^2 )=√10.解法二由{■(3x+y"-" 6=0"," @x^2+y^2 "-" 2y"-" 4=0"," )┤消去y,得x2-3x+2=0.設兩交點A,B的坐標分別為A(x1,y1),B(x2,y2),則由根與系數(shù)的關系,得x1+x2=3,x1·x2=2.∴|AB|=√("(" x_2 "-" x_1 ")" ^2+"(" y_2 "-" y_1 ")" ^2 )=√(10"[(" x_1+x_2 ")" ^2 "-" 4x_1 x_2 "]" ┴" " )=√(10×"(" 3^2 "-" 4×2")" )=√10,即弦AB的長為√10.解法三圓C:x2+y2-2y-4=0可化為x2+(y-1)2=5,其圓心坐標(0,1),半徑r=√5,點(0,1)到直線l的距離為d=("|" 3×0+1"-" 6"|" )/√(3^2+1^2 )=√10/2,所以半弦長為("|" AB"|" )/2=√(r^2 "-" d^2 )=√("(" √5 ")" ^2 "-" (√10/2) ^2 )=√10/2,所以弦長|AB|=√10.
直線的兩點式方程教學設計人教A版高中數(shù)學選擇性必修第一冊
解析：①過原點時，直線方程為y＝－34x.②直線不過原點時，可設其方程為xa＋ya＝1，∴4a＋－3a＝1，∴a＝1.∴直線方程為x＋y－1＝0.所以這樣的直線有2條，選B.答案：B4.若點P(3,m)在過點A(2,-1),B(-3,4)的直線上,則m= . 解析:由兩點式方程得,過A,B兩點的直線方程為(y"-(-" 1")" )/(4"-(-" 1")" )=(x"-" 2)/("-" 3"-" 2),即x+y-1=0.又點P(3,m)在直線AB上,所以3+m-1=0,得m=-2.答案:-2 5.直線ax+by=1(ab≠0)與兩坐標軸圍成的三角形的面積是 . 解析:直線在兩坐標軸上的截距分別為1/a 與 1/b,所以直線與坐標軸圍成的三角形面積為1/(2"|" ab"|" ).答案:1/(2"|" ab"|" )6.已知三角形的三個頂點A(0,4)，B(－2,6)，C(－8,0)．(1)求三角形三邊所在直線的方程；(2)求AC邊上的垂直平分線的方程．解析(1)直線AB的方程為y－46－4＝x－0－2－0，整理得x＋y－4＝0；直線BC的方程為y－06－0＝x＋8－2＋8，整理得x－y＋8＝0；由截距式可知，直線AC的方程為x－8＋y4＝1，整理得x－2y＋8＝0.(2)線段AC的中點為D(－4,2)，直線AC的斜率為12，則AC邊上的垂直平分線的斜率為－2，所以AC邊的垂直平分線的方程為y－2＝－2(x＋4)，整理得2x＋y＋6＝0.
直線的一般式方程教學設計人教A版高中數(shù)學選擇性必修第一冊
解析:當a0時,直線ax-by=1在x軸上的截距1/a0,在y軸上的截距-1/a>0.只有B滿足.故選B.答案:B 3．過點(1,0)且與直線x－2y－2＝0平行的直線方程是( ) A．x－2y－1＝0 B．x－2y＋1＝0C．2x＋y＝2＝0 D．x＋2y－1＝0答案A 解析：設所求直線方程為x－2y＋c＝0，把點(1,0)代入可求得c＝－1.所以所求直線方程為x－2y－1＝0.故選A.4．已知兩條直線y＝ax－2和3x－(a＋2)y＋1＝0互相平行，則a＝________.答案：1或－3 解析：依題意得：a(a＋2)＝3×1，解得a＝1或a＝－3.5．若方程(m2－3m＋2)x＋(m－2)y－2m＋5＝0表示直線．(1)求實數(shù)m的范圍；(2)若該直線的斜率k＝1，求實數(shù)m的值．解析： (1)由m2－3m＋2＝0，m－2＝0，解得m＝2，若方程表示直線，則m2－3m＋2與m－2不能同時為0，故m≠2.(2)由－?m2－3m＋2?m－2＝1，解得m＝0.